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    <script>
        //柯里化思想

        //请实现以下效果
        // function add (a, b, c) {
        //     return a + b + c
        // }
        // console.log(add.length);

        // const res = add(1, 2, 3) //6

        //要求声明一个curry函数，函数add经过curry函数的处理后，每次调用只能接收一个参数
        const add = (...he) => {
            return he.reduce((a, b) => {
                return a + b
            })
        }
        // console.log(add(1,2,3));
        const curry = (fn) => {
            const args = []
            return function res(...arg) {
                if (arg.length === 0) {
                    return fn(...args)
                } else
                if (arg.length === 1) {
                    args.push(...arg)
                    return res
                }
            }
        }
        const addCurry = curry(add)
        // console.log(curry(add)(1)(2)(3)());
        // console.log(addCurry);
        const res2 = addCurry(1)(2)(3)() //6
        console.log(res2);
    </script>
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